What is the asymptotes of f(x)=(x^2-3x)/(x^2-9) ?

The asymptotes of f(x)=(x^2-3x)/(x^2-9) is Vertical: x=-3,Horizontal: y=1

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asymptotes of f(x)=(x^2-3x)/(x^2-9)

asymptotes

f (x) = \frac{x ^{2} - 3 x}{x ^{2} - 9}

Vertical : x = - 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 9} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 9} :

None

Vertical : x = - 3, Horizontal : y = 1

\frac{x ^{2} - 4}{x - 2}

34

f (x) = \frac{1}{2} x^{3} - 15

f (x) = \frac{x ( 3 x - 1 )}{2}

What is the asymptotes of f(x)=(x^2-3x)/(x^2-9) ?
The asymptotes of f(x)=(x^2-3x)/(x^2-9) is Vertical: x=-3,Horizontal: y=1