What is the perpendicular (1,6),y=-1/4 x+3 ?

The perpendicular (1,6),y=-1/4 x+3 is False

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perpendicular (1,6),y=-1/4 x+3

perpendicular

(1, 6), y = - \frac{1}{4} x + 3

False

Solution steps

Find the slope of

(1, 6) : m = 0

Find the slope of

y = - \frac{1}{4} x + 3 : m = - \frac{1}{4}

0

is not the negative reciprocal of

- \frac{1}{4}

Hence the given lines are not perpendicular

f (x) = x^{\frac{2}{5}} (x - 5)

f (x) = 2 x^{2} - 3 x + 1

- x^{2} + 8 x - 9

x + 2 y = 16

f (x) = 2 x + \frac{50}{x}

What is the perpendicular (1,6),y=-1/4 x+3 ?
The perpendicular (1,6),y=-1/4 x+3 is False