What is the inverse of f(x)=(6x-2)/(x^2) ?

The inverse of f(x)=(6x-2)/(x^2) is (3+sqrt(-2x+9))/x ,(3-sqrt(-2x+9))/x

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inverse of f(x)=(6x-2)/(x^2)

inverse

f (x) = \frac{6 x - 2}{x ^{2}}

\frac{3 + - 2 x + 9}{x}, \frac{3 - - 2 x + 9}{x}

Solution steps

y = \frac{6 x - 2}{x ^{2}}

Replace

x

with

y

x = \frac{6 y - 2}{y ^{2}}

Solve for

y, x = \frac{6 y - 2}{y ^{2}}

\frac{3 + - 2 x + 9}{x}, \frac{3 - - 2 x + 9}{x}

f (x) = - x^{2} + 8 x - 15

2 sin (5 x - 3)

f (x) = 12 - x

f (x) = \frac{1}{x} - 2

y = \frac{2}{3} x - 1

What is the inverse of f(x)=(6x-2)/(x^2) ?
The inverse of f(x)=(6x-2)/(x^2) is (3+sqrt(-2x+9))/x ,(3-sqrt(-2x+9))/x