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Popular >

distance (-5,-8),(4,0)

Solution

distance

(- 5, - 8), (4, 0)

Solution

145

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 5, - 8)

and

(4, 0)

is

= (4 - (- 5))^{2} + (0 - (- 8))^{2}

Simplify

= 145

Popular Examples

range of (x^2+x)/(-2x^2-2x+12)range

\frac{x ^{2} + x}{- 2 x ^{2} - 2 x + 12}

parity sin(2x+3)parity

sin (2 x + 3)

parallel y= 3/2 x+6,(-4,3)parallel

y = \frac{3}{2} x + 6, (- 4, 3)

parallel y=x+2,(4,9)parallel

y = x + 2, (4, 9)

domain of f(x)=x+9/x domain

f (x) = x + \frac{9}{x}

Frequently Asked Questions (FAQ)

What is the distance (-5,-8),(4,0) ?
The distance (-5,-8),(4,0) is square root of 145