What is the perpendicular 2x-5y=-10,(4,-5) ?

The perpendicular 2x-5y=-10,(4,-5) is y=-5/2 x+5

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perpendicular 2x-5y=-10,(4,-5)

perpendicular

2 x - 5 y = - 10, (4, - 5)

y = - \frac{5}{2} x + 5

Solution steps

Find the line

y = mx + b

perpendicular to

2 x - 5 y = - 10

that passes through

(4, - 5)

Find the slope of

2 x - 5 y = - 10 : m = \frac{2}{5}

Compute the slope of the perpendicular line:

m_{p} = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(4, - 5) : y = - \frac{5}{2} x + 5

y = - \frac{5}{2} x + 5

f (x) = \frac{( 3 x - 7 )}{x + 1}

f (x) = x x - 1

- 2 cos (x)

f (x) = 4 + \frac{1}{3} x

x = - 2

What is the perpendicular 2x-5y=-10,(4,-5) ?
The perpendicular 2x-5y=-10,(4,-5) is y=-5/2 x+5