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Popular >

range of y=-x^2+1

Solution

range

y = - x^{2} + 1

Solution

f (x) \leq 1

+1

Interval Notation

(- \infty, 1]

Solution steps

Vertex of

- x^{2} + 1 :

Maximum

(0, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 1)

f (x) \leq 1

Popular Examples

parity f(x)=\sqrt[3]{x}parity

extreme f(x)=-5(x-3)^{6/7}+9 extreme points

f (x) = - 5 (x - 3)^{\frac{6}{7}} + 9

slope ofintercept y-2= 1/3 (x-3)slope intercept

y - 2 = \frac{1}{3} (x - 3)

line (1,20),(3,12)line

(1, 20), (3, 12)

inverse of x^3+16 inverse

x^{3} + 16

Frequently Asked Questions (FAQ)

What is the range of y=-x^2+1 ?
The range of y=-x^2+1 is f(x)<= 1