What is the critical 3x^2-2x+1 ?

The critical 3x^2-2x+1 is x= 1/3

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critical 3x^2-2x+1

critical points

3 x^{2} - 2 x + 1

x = \frac{1}{3}

Solution steps

3 x^{2} - 2 x + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

3 x^{2} - 2 x + 1 : - \infty < x < \infty

All critical points are in domain

x = \frac{1}{3}

5.75 cos (12 t) + 7.88

2 x - 5 y - 2 = 0, (1, - 2)

(2.07, 22.54), (- 8.68, - 22.32)

f (x) = \frac{x - 4}{3 x - x ^{2}}

f (x) = x^{2} - (y - 3)^{2} = 16