What is the range of f(x)=sqrt(x)-8 ?

The range of f(x)=sqrt(x)-8 is f(x)>=-8

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range of f(x)=sqrt(x)-8

range

f (x) = x - 8

f (x) \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = - 8

f (x) \geq - 8

\frac{x ^{2} + 2 x}{x ^{3} - 2 x ^{2} - 8 x}

x^{2} - x - 6

f (x) = \frac{x}{x - 1}

f (x) = 2 x + 3 - 1

f (x) = (3.6) (5.1) (7.14)