What is the domain of f(x)= 1/(sqrt(2x+3)) ?

The domain of f(x)= 1/(sqrt(2x+3)) is x>-3/2

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domain of f(x)= 1/(sqrt(2x+3))

domain

f (x) = \frac{1}{2 x + 3}

x > - \frac{3}{2}

Interval Notation

(- \frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{2}

Find undefined (singularity) points:

x = - \frac{3}{2}

Combine real regions and undefined points for final function domain

x > - \frac{3}{2}

x e^{\frac{1}{x}}

f (x) = cos (t)

f (x) = 4 x^{3} - 3 x^{2} - 60 x + 17

\frac{1}{x ^{2} + 3}

f (x) = 2 x^{4}

What is the domain of f(x)= 1/(sqrt(2x+3)) ?
The domain of f(x)= 1/(sqrt(2x+3)) is x>-3/2