What is the inverse of f(x)= 1/4 x^3-5 ?

The inverse of f(x)= 1/4 x^3-5 is cube root of 4x+20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/4 x^3-5

inverse

f (x) = \frac{1}{4} x^{3} - 5

Solution steps

y = \frac{1}{4} x^{3} - 5

Replace

x

with

y

x = \frac{1}{4} y^{3} - 5

Solve for

y, x = \frac{1}{4} y^{3} - 5

f (x) = - 2 cos (3 x)

lo g_{10} (x + 4)

- 4 sin (x + \frac{π}{3})

(m, p), (0, 0)

y = 6^{x} + 2

What is the inverse of f(x)= 1/4 x^3-5 ?
The inverse of f(x)= 1/4 x^3-5 is cube root of 4x+20