What is the inverse of f(x)=(x-1)/(1+3x) ?

The inverse of f(x)=(x-1)/(1+3x) is (-1-x)/(3x-1)

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inverse of f(x)=(x-1)/(1+3x)

inverse

f (x) = \frac{x - 1}{1 + 3 x}

\frac{- 1 - x}{3 x - 1}

Solution steps

y = \frac{x - 1}{1 + 3 x}

Replace

x

with

y

x = \frac{y - 1}{1 + 3 y}

Solve for

y, x = \frac{y - 1}{1 + 3 y}

\frac{- 1 - x}{3 x - 1}

f (2) = \frac{1}{t} + 1

f (x) = \frac{1}{- x ^{2} + 3 x}

2 ∣ x ∣

f (x) = 3 x + 4

f (x) = 4 x^{2} - 8

What is the inverse of f(x)=(x-1)/(1+3x) ?
The inverse of f(x)=(x-1)/(1+3x) is (-1-x)/(3x-1)