What is the inverse of f(x)=100(1-t/(40))^2 ?

The inverse of f(x)=100(1-t/(40))^2 is -4sqrt(t)+40,4sqrt(t)+40

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=100(1-t/(40))^2

inverse

f (x) = 100 (1 - \frac{t}{40})^{2}

- 4 t + 40, 4 t + 40

Solution steps

x = 100 (1 - \frac{t}{40})^{2}

Replace

t

with

x

t = 100 (1 - \frac{x}{40})^{2}

Solve for

x, t = 100 (1 - \frac{x}{40})^{2}

- 4 t + 40, 4 t + 40

y = 4 lo g_{x} (3)

f (x) = \frac{x - 3}{9 x + 4}

f (x) = \frac{x ^{2}}{x ^{2} + 1}

(3, 1), (- 1, - 1)

f (x) = 8 x^{5}

What is the inverse of f(x)=100(1-t/(40))^2 ?
The inverse of f(x)=100(1-t/(40))^2 is -4sqrt(t)+40,4sqrt(t)+40