What is the domain of f(x)= 1/(sqrt(3-2x-x^2)) ?

The domain of f(x)= 1/(sqrt(3-2x-x^2)) is -3<x<1

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domain of f(x)= 1/(sqrt(3-2x-x^2))

domain

f (x) = \frac{1}{3 - 2 x - x ^{2}}

- 3 < x < 1

Interval Notation

(- 3, 1)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 1

Find undefined (singularity) points:

x = - 3, x = 1

Combine real regions and undefined points for final function domain

- 3 < x < 1

f (x) = - 2

f (x) = x - 2 - 5

(- 1 4), (- 1 7)

2 (x + 3)^{2} - 3

What is the domain of f(x)= 1/(sqrt(3-2x-x^2)) ?
The domain of f(x)= 1/(sqrt(3-2x-x^2)) is -3<x<1