What is the inverse of f(x)=4x^2-16 ?

The inverse of f(x)=4x^2-16 is (sqrt(x+16))/2 ,-(sqrt(x+16))/2

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inverse of f(x)=4x^2-16

inverse

f (x) = 4 x^{2} - 16

\frac{x + 16}{2}, - \frac{x + 16}{2}

Solution steps

y = 4 x^{2} - 16

Replace

x

with

y

x = 4 y^{2} - 16

Solve for

y, x = 4 y^{2} - 16

\frac{x + 16}{2}, - \frac{x + 16}{2}

f (x) = 2 ln (x^{2} + 1)

f (x) = e^{- x}

x^{2} - 6 x

f (x) = \frac{2}{x + 4}

f (x) = \frac{3 x ^{3} - 1}{x ^{2} - 2 x}

What is the inverse of f(x)=4x^2-16 ?
The inverse of f(x)=4x^2-16 is (sqrt(x+16))/2 ,-(sqrt(x+16))/2