What is the domain of f(x)= 1/(10(\frac{1){x+2})-4} ?

The domain of f(x)= 1/(10(\frac{1){x+2})-4} is x 1/2

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domain of f(x)= 1/(10(\frac{1){x+2})-4}

domain

f (x) = \frac{1}{10 ( \frac{1}{x + 2} ) - 4}

x < - 2 or - 2 < x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, - 2) \cup (- 2, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}, x = - 2

The function domain

x < - 2 or - 2 < x < \frac{1}{2} or x > \frac{1}{2}

f (x) = \frac{2 x - 3 x - 2}{4 x - 1}

f (x) = \frac{( x + 3 ) ^{2}}{4 x - 1}

f (x) = x^{2} - 9

\frac{1}{3} x - 3

y = 3 (x + 1)

What is the domain of f(x)= 1/(10(\frac{1){x+2})-4} ?
The domain of f(x)= 1/(10(\frac{1){x+2})-4} is x<-2\lor-2<x< 1/2 \lor x> 1/2