What is the inverse of f(x)=((x+3))/(x+6) ?

The inverse of f(x)=((x+3))/(x+6) is (3-6x)/(x-1)

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inverse of f(x)=((x+3))/(x+6)

inverse

f (x) = \frac{( x + 3 )}{x + 6}

\frac{3 - 6 x}{x - 1}

Solution steps

y = \frac{x + 3}{x + 6}

Replace

x

with

y

x = \frac{y + 3}{y + 6}

Solve for

y, x = \frac{y + 3}{y + 6}

\frac{3 - 6 x}{x - 1}

f (x) = \frac{- 2}{x + 1} - 1

f (x) = 4 x^{2} - 6

- 5 cos (\frac{x}{3} + \frac{π}{2}) - 4

(- 1, 3), (3, 5)

\frac{- 5 x + 25}{9}

What is the inverse of f(x)=((x+3))/(x+6) ?
The inverse of f(x)=((x+3))/(x+6) is (3-6x)/(x-1)