What is the inverse of f(x)=\sqrt[3]{x}-9 ?

The inverse of f(x)=\sqrt[3]{x}-9 is x^3+27x^2+243x+729

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inverse of f(x)=\sqrt[3]{x}-9

inverse

x^{3} + 27 x^{2} + 243 x + 729

Solution steps

Replace

x

with

y

Solve for

x^{3} + 27 x^{2} + 243 x + 729

f (x) = 2 x^{3} - 3 x

f (x) = \frac{( x ^{2} - 1 )}{x + 1}

f (x) = \frac{x + 2}{x + 10}

f (x) = \frac{- x ^{2} - 4 x + 5}{4 x - 4}

f (x) = \frac{x - 4}{x - 6}

What is the inverse of f(x)=\sqrt[3]{x}-9 ?
The inverse of f(x)=\sqrt[3]{x}-9 is x^3+27x^2+243x+729