What is the extreme f(x)=-4x^3+6x^2-5 ?

The extreme f(x)=-4x^3+6x^2-5 is Minimum(0,-5),Maximum(1,-3)

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extreme f(x)=-4x^3+6x^2-5

extreme points

f (x) = - 4 x^{3} + 6 x^{2} - 5

Minimum (0, - 5), Maximum (1, - 3)

Solution steps

f^{'} (x) = - 12 x^{2} + 12 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

- 4 x^{3} + 6 x^{2} - 5 : - 5

Minimum (0, - 5)

Plug

x = 1

into

- 4 x^{3} + 6 x^{2} - 5 : - 3

Maximum (1, - 3)

Minimum (0, - 5), Maximum (1, - 3)

f (x) = 2 \cdot 3^{x - 4}

f (x) = \frac{5}{3} sin (- \frac{2 π}{3} x)

y = 8 x - 3, (6, 2)

f (x) = \frac{\frac{x}{x + 7}}{\frac{x}{x + 7} + 7}

f (x) = \frac{5 x + 9}{6}

What is the extreme f(x)=-4x^3+6x^2-5 ?
The extreme f(x)=-4x^3+6x^2-5 is Minimum(0,-5),Maximum(1,-3)