What is the critical (4x^2)/(x^2-1) ?

The critical (4x^2)/(x^2-1) is x=0

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critical (4x^2)/(x^2-1)

critical points

\frac{4 x ^{2}}{x ^{2} - 1}

x = 0

Solution steps

\frac{4 x ^{2}}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{4 x ^{2}}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

\frac{4 x ^{2}}{x ^{2} - 1}

is not defined at

x = - 1, x = 1

, therefore:

x = 0

f (x) = \frac{5}{4 + x}

f (x) = 4 x + 3

y = 5 x + 2

2 ln (x - 1) + 5

y = - 8 x + 3, (2, 1)