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Popular >

distance (-5,-1),(-2,1)

Solution

distance

(- 5, - 1), (- 2, 1)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 5, - 1)

and

(- 2, 1)

is

= (- 2 - (- 5))^{2} + (1 - (- 1))^{2}

Simplify

= 13

Popular Examples

inflection f(x)=19x^4-114x^2 inflection points

f (x) = 19 x^{4} - 114 x^{2}

inverse of f(x)=x^2+16x-4 inverse

f (x) = x^{2} + 16 x - 4

critical (x+4)/(8x)critical points

\frac{x + 4}{8 x}

intercepts of f(x)=x^2-sqrt(x)intercepts

f (x) = x^{2} - x

extreme f(x)=(16x^2-16)^{1/5}extreme points

f (x) = (16 x^{2} - 16)^{\frac{1}{5}}

Frequently Asked Questions (FAQ)

What is the distance (-5,-1),(-2,1) ?
The distance (-5,-1),(-2,1) is square root of 13