What is the inverse of f(x)=(x+2)^2-5 ?

The inverse of f(x)=(x+2)^2-5 is sqrt(x+5)-2,-sqrt(x+5)-2

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inverse of f(x)=(x+2)^2-5

inverse

f (x) = (x + 2)^{2} - 5

x + 5 - 2, - x + 5 - 2

Solution steps

y = (x + 2)^{2} - 5

Replace

x

with

y

x = (y + 2)^{2} - 5

Solve for

y, x = (y + 2)^{2} - 5

x + 5 - 2, - x + 5 - 2

- 4 + lo g_{2} (5 - 2 x)

f (x) = \frac{3 - x}{x}

f (x) = \frac{x ^{2}}{x ^{2} + 4}

csc (x)

- 3 x^{3} + 9 x^{2} + 12 x

What is the inverse of f(x)=(x+2)^2-5 ?
The inverse of f(x)=(x+2)^2-5 is sqrt(x+5)-2,-sqrt(x+5)-2