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Popular >

range of x^2-16x+63

Solution

range

x^{2} - 16 x + 63

Solution

f (x) \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

Vertex of

x^{2} - 16 x + 63 :

Minimum

(8, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (8, - 1)

f (x) \geq - 1

Popular Examples

intercepts of f(x)=-2x^3+10x^2+48x intercepts

f (x) = - 2 x^{3} + 10 x^{2} + 48 x

slope of 3y+x=12 slope

3 y + x = 12

range of (x+2)/(x+4)range

\frac{x + 2}{x + 4}

domain of f(x)=-x+10 domain

f (x) = - x + 10

domain of f(x)=3x-2/(sqrt(x+1))domain

f (x) = 3 x - \frac{2}{x + 1}

Frequently Asked Questions (FAQ)

What is the range of x^2-16x+63 ?
The range of x^2-16x+63 is f(x)>=-1