What is the domain of f(x)=(x+3)/(x^2-9) ?

The domain of f(x)=(x+3)/(x^2-9) is x 3

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domain of f(x)=(x+3)/(x^2-9)

domain

f (x) = \frac{x + 3}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

y = 3 sin (\frac{x}{2} \frac{- π}{3})

f (x) = (x - 3) (x + 2)

y = - (x + 3)^{2} - 1

- 2 y - 5 x = 2 - 10 x

f (x) = - 2 x^{2} + 5 x - 6

What is the domain of f(x)=(x+3)/(x^2-9) ?
The domain of f(x)=(x+3)/(x^2-9) is x<-3\lor-3<x<3\lor x>3