What is the inverse of f(x)=-0.06(x+2)^4+1.5 ?

The inverse of f(x)=-0.06(x+2)^4+1.5 is \sqrt[4]{-(25(2x-3))/3}-2,-\sqrt[4]{-(25(2x-3))/3}-2

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inverse of f(x)=-0.06(x+2)^4+1.5

inverse

f (x) = - 0.06 (x + 2)^{4} + 1.5

Solution steps

y = - 0.06 (x + 2)^{4} + 1.5

Replace

x

with

y

x = - 0.06 (y + 2)^{4} + 1.5

Solve for

y, x = - 0.06 (y + 2)^{4} + 1.5

f (x) = y^{2} + 17

f (x) = \frac{e ^{x} + e ^{- x}}{2}

f (x) = x^{4} - 7 x^{3}

cos (3 x)

f (x) = 5 cos (x)

What is the inverse of f(x)=-0.06(x+2)^4+1.5 ?
The inverse of f(x)=-0.06(x+2)^4+1.5 is \sqrt[4]{-(25(2x-3))/3}-2,-\sqrt[4]{-(25(2x-3))/3}-2