What is the critical f(x)=5+4/x+(16)/(x^2) ?

The critical f(x)=5+4/x+(16)/(x^2) is x=-8

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critical f(x)=5+4/x+(16)/(x^2)

critical points

f (x) = 5 + \frac{4}{x} + \frac{16}{x ^{2}}

x = - 8

Solution steps

5 + \frac{4}{x} + \frac{16}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 8, x = 0

Identify critical points not in

f (x)

domain

Domain of

5 + \frac{4}{x} + \frac{16}{x ^{2}} : x < 0 or x > 0

5 + \frac{4}{x} + \frac{16}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - 8

f (x) = \frac{1}{14 - t}

y = \frac{- 8 x ^{3}}{3 x ^{2} - 1}

y = \frac{1}{x} - 3

f (x) = x^{2} + 3

\frac{4}{x}

What is the critical f(x)=5+4/x+(16)/(x^2) ?
The critical f(x)=5+4/x+(16)/(x^2) is x=-8