What is the domain of sqrt(x^2-9) ?

The domain of sqrt(x^2-9) is x = 3

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domain of sqrt(x^2-9)

domain

x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

(0, - 7), (- 5, - 9)

f (x) = \frac{5 x}{x + 3} - 3

14 x + 6 y = 36

f (x) = \frac{x}{2 x - 3}

f (x) = 6 lo g_{5} (- 4 x) - 7

What is the domain of sqrt(x^2-9) ?
The domain of sqrt(x^2-9) is x<=-3\lor x>= 3