What is the intercepts of f(x)=y^2=x+16 ?

The intercepts of f(x)=y^2=x+16 is X Intercepts: (-16,0),Y Intercepts: (0,16)

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intercepts of f(x)=y^2=x+16

intercepts

f (x) = y^{2} = x + 16

X Intercepts : (- 16, 0), Y Intercepts : (0, 16)

Solution steps

x -

axis interception points of

x + 16 : (- 16, 0)

y -

axis interception point of

x + 16 : (0, 16)

X Intercepts : (- 16, 0), Y Intercepts : (0, 16)

lo g_{10} (x^{3} - x)

f (x) = 2 x^{2} - x - 1

3 cos (θ)

\frac{x ^{2} + 4 + x}{2}

f (x) = \frac{( x ^{2} - 2 x - 3 )}{( x + 2 )}

What is the intercepts of f(x)=y^2=x+16 ?
The intercepts of f(x)=y^2=x+16 is X Intercepts: (-16,0),Y Intercepts: (0,16)