What is the domain of g(x)=\sqrt[4]{x} ?

The domain of g(x)=\sqrt[4]{x} is x>= 0

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domain of g(x)=\sqrt[4]{x}

domain

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = x^{2} + y^{2} = 9

f (x) = \frac{x + 6}{x - 2}

f (x) = 3 x - 5

f (x) = 10 x - 8 + 2

x^{2} - 4

What is the domain of g(x)=\sqrt[4]{x} ?
The domain of g(x)=\sqrt[4]{x} is x>= 0