What is the inverse of f(x)=4x^2+16x+32 ?

The inverse of f(x)=4x^2+16x+32 is (-4+sqrt(x-16))/2 ,-(sqrt(x-16)+4)/2

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inverse of f(x)=4x^2+16x+32

inverse

f (x) = 4 x^{2} + 16 x + 32

\frac{- 4 + x - 16}{2}, - \frac{x - 16 + 4}{2}

Solution steps

y = 4 x^{2} + 16 x + 32

Replace

x

with

y

x = 4 y^{2} + 16 y + 32

Solve for

y, x = 4 y^{2} + 16 y + 32

\frac{- 4 + x - 16}{2}, - \frac{x - 16 + 4}{2}

x^{2} + 2 x - 2

f (x) = 3^{x} + 4

2 (\frac{1}{2})^{x} - 2

f (x) = - 5 tan (2 x - \frac{π}{3})

x^{4} - 4 x^{3} + 6

What is the inverse of f(x)=4x^2+16x+32 ?
The inverse of f(x)=4x^2+16x+32 is (-4+sqrt(x-16))/2 ,-(sqrt(x-16)+4)/2