What is the domain of f(x)=sqrt(\sqrt[3]{1-x)} ?

The domain of f(x)=sqrt(\sqrt[3]{1-x)} is x<= 1

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domain of f(x)=sqrt(\sqrt[3]{1-x)}

domain

x \leq 1

Interval Notation

(- \infty, 1]

Solution steps

Find non-negative values for radicals:

x \leq 1

The function domain

x \leq 1

f (x) = \frac{x - 2}{x ^{2} + 3 x - 10}

5 + 8 x

f (x) = x^{2} - 7 x - 18

f (x) = 3 (\frac{1}{4})^{x}

(3.3) (8.9)

What is the domain of f(x)=sqrt(\sqrt[3]{1-x)} ?
The domain of f(x)=sqrt(\sqrt[3]{1-x)} is x<= 1