What is the inverse of f(x)=((x+1))/(4x+1) ?

The inverse of f(x)=((x+1))/(4x+1) is (1-x)/(4x-1)

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inverse of f(x)=((x+1))/(4x+1)

inverse

f (x) = \frac{( x + 1 )}{4 x + 1}

\frac{1 - x}{4 x - 1}

Solution steps

y = \frac{x + 1}{4 x + 1}

Replace

x

with

y

x = \frac{y + 1}{4 y + 1}

Solve for

y, x = \frac{y + 1}{4 y + 1}

\frac{1 - x}{4 x - 1}

f (x) = \frac{x + 5}{x ^{2} + 3 x - 10}

x + y^{2} = 4

4 x - y = 12

f (x) = \frac{6}{x}

What is the inverse of f(x)=((x+1))/(4x+1) ?
The inverse of f(x)=((x+1))/(4x+1) is (1-x)/(4x-1)