What is the domain of g(x)= 1/(2sqrt(8-x)) ?

The domain of g(x)= 1/(2sqrt(8-x)) is x<8

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domain of g(x)= 1/(2sqrt(8-x))

domain

g (x) = \frac{1}{2 8 - x}

x < 8

Interval Notation

(- \infty, 8)

Solution steps

Find non-negative values for radicals:

x \leq 8

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

x < 8

f (x) = \frac{3 x - 1}{2 x + 3}

f (x) = \frac{7 x - 8}{x ^{2} - 16}

\frac{x}{x + 1} + x^{3}

\frac{2}{x - 4}

f (x) = x^{3} - 9 x^{2} + 27 x - 5

What is the domain of g(x)= 1/(2sqrt(8-x)) ?
The domain of g(x)= 1/(2sqrt(8-x)) is x<8