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Popular >

extreme f(x)=x^3-9x^2+27x-5

Solution

extreme points

f (x) = x^{3} - 9 x^{2} + 27 x - 5

Solution

Saddle (3, 22)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x + 27

Find intervals:

Increasing

: - \infty < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

x^{3} - 9 x^{2} + 27 x - 5 : 22

Saddle (3, 22)

Popular Examples

intercepts of-2x^3+13x^2-17x-12 intercepts

- 2 x^{3} + 13 x^{2} - 17 x - 12

inverse of f(x)= 1/4 (x-4)^3 inverse

f (x) = \frac{1}{4} (x - 4)^{3}

extreme f(x)=x^2-8x+21 extreme points

f (x) = x^{2} - 8 x + 21

critical (x^2)/(x-3)critical points

\frac{x ^{2}}{x - 3}

inverse of f(x)=x^2+8x inverse

f (x) = x^{2} + 8 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-9x^2+27x-5 ?
The extreme f(x)=x^3-9x^2+27x-5 is Saddle(3,22)