What is the inverse of f(x)= 1/4 (x-4)^3 ?

The inverse of f(x)= 1/4 (x-4)^3 is \sqrt[3]{4}\sqrt[3]{x}+4

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inverse of f(x)= 1/4 (x-4)^3

inverse

f (x) = \frac{1}{4} (x - 4)^{3}

Solution steps

y = \frac{1}{4} (x - 4)^{3}

Replace

x

with

y

x = \frac{1}{4} (y - 4)^{3}

Solve for

y, x = \frac{1}{4} (y - 4)^{3}

f (x) = x^{2} - 8 x + 21

\frac{x ^{2}}{x - 3}

f (x) = x^{2} + 8 x

6 x - 9

f (x) = \frac{1}{x} + 2

What is the inverse of f(x)= 1/4 (x-4)^3 ?
The inverse of f(x)= 1/4 (x-4)^3 is \sqrt[3]{4}\sqrt[3]{x}+4