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Popular >

extreme f(x)=x^2-8x+21

Solution

extreme points

f (x) = x^{2} - 8 x + 21

Solution

Minimum (4, 5)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 21 : 5

Minimum (4, 5)

Popular Examples

critical (x^2)/(x-3)critical points

\frac{x ^{2}}{x - 3}

inverse of f(x)=x^2+8x inverse

f (x) = x^{2} + 8 x

inverse of 6x-9 inverse

6 x - 9

range of f(x)=sqrt(1/x+2)range

f (x) = \frac{1}{x} + 2

inverse of (x+3)^2-1 inverse

(x + 3)^{2} - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+21 ?
The extreme f(x)=x^2-8x+21 is Minimum(4,5)