What is the inverse of f(x)=x^2+8x ?

The inverse of f(x)=x^2+8x is -4+sqrt(x+16),-sqrt(x+16)-4

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inverse of f(x)=x^2+8x

inverse

f (x) = x^{2} + 8 x

- 4 + x + 16, - x + 16 - 4

Solution steps

y = x^{2} + 8 x

Replace

x

with

y

x = y^{2} + 8 y

Solve for

y, x = y^{2} + 8 y

- 4 + x + 16, - x + 16 - 4

6 x - 9

f (x) = \frac{1}{x} + 2

(x + 3)^{2} - 1

(2, - 1), (3, 6)

(x^{6} + 7) (x^{10} + 9)

What is the inverse of f(x)=x^2+8x ?
The inverse of f(x)=x^2+8x is -4+sqrt(x+16),-sqrt(x+16)-4