What is the domain of (x^2-9)/(x^2-2x-1) ?

The domain of (x^2-9)/(x^2-2x-1) is x 1+sqrt(2)

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domain of (x^2-9)/(x^2-2x-1)

domain

\frac{x ^{2} - 9}{x ^{2} - 2 x - 1}

x < 1 - 2 or 1 - 2 < x < 1 + 2 or x > 1 + 2

Interval Notation

(- \infty, 1 - 2) \cup (1 - 2, 1 + 2) \cup (1 + 2, \infty)

Solution steps

Find undefined (singularity) points:

x = 1 + 2, x = 1 - 2

The function domain

x < 1 - 2 or 1 - 2 < x < 1 + 2 or x > 1 + 2

(3, 0), (0, 4)

\frac{x - 2}{3 x + 7}

f (x) = \frac{2 x ^{2} + 2 x - 4}{x ^{2} + x}

- 6 x^{3} + 9 x^{2} + 36 x

3 - 2 x - x^{2}

What is the domain of (x^2-9)/(x^2-2x-1) ?
The domain of (x^2-9)/(x^2-2x-1) is x<1-sqrt(2)\lor 1-sqrt(2)<x<1+sqrt(2)\lor x>1+sqrt(2)