What is the inverse of f(x)=2-x-x^2 ?

The inverse of f(x)=2-x-x^2 is -(1+sqrt(-4x+9))/2 ,-(1-sqrt(-4x+9))/2

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inverse of f(x)=2-x-x^2

inverse

f (x) = 2 - x - x^{2}

- \frac{1 + - 4 x + 9}{2}, - \frac{1 - - 4 x + 9}{2}

Solution steps

y = 2 - x - x^{2}

Replace

x

with

y

x = 2 - y - y^{2}

Solve for

y, x = 2 - y - y^{2}

- \frac{1 + - 4 x + 9}{2}, - \frac{1 - - 4 x + 9}{2}

f (x) = cot (x + \frac{π}{4})

f (x) = x 4 - x

y = 2^{- x} + 1

\frac{x ^{2} - 1}{4 x + 16}

f (x) = \frac{x + 3}{x + 1}

What is the inverse of f(x)=2-x-x^2 ?
The inverse of f(x)=2-x-x^2 is -(1+sqrt(-4x+9))/2 ,-(1-sqrt(-4x+9))/2