en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=t^2-7t+10

Solution

extreme points

f (x) = t^{2} - 7 t + 10

Solution

Minimum (\frac{7}{2}, - \frac{9}{4})

Solution steps

f^{'} (t) = 2 t - 7

Find intervals:

Decreasing

: - \infty < t < \frac{7}{2},

Increasing

: \frac{7}{2} < t < \infty

Plug

t = \frac{7}{2}

into

t^{2} - 7 t + 10 : - \frac{9}{4}

Minimum (\frac{7}{2}, - \frac{9}{4})

Popular Examples

inverse of f(x)=(4x+7)/(x+4)inverse

f (x) = \frac{4 x + 7}{x + 4}

symmetry-(x+1)^2-4 symmetry

- (x + 1)^{2} - 4

slope of 4x+5y=-30 slope

4 x + 5 y = - 30

line (5,0),(8,6)line

(5, 0), (8, 6)

domain of (sqrt(4x))/(x+9)domain

\frac{4 x}{x + 9}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=t^2-7t+10 ?
The extreme f(x)=t^2-7t+10 is Minimum(7/2 ,-9/4)