What is the range of y(θ)=3cos(θ+pi) ?

The range of y(θ)=3cos(θ+pi) is -3<= f(θ)<= 3

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range of y(θ)=3cos(θ+pi)

range

y (θ) = 3 cos (θ + π)

- 3 \leq f (θ) \leq 3

Interval Notation

[- 3, 3]

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (θ + π) \leq 1

- 1 \leq cos (θ + π) \leq 1

Multiply the edges of the range by:

3

- 3 \leq 3 cos (θ + π) \leq 3

Therefore the range is

- 3 \leq f (θ) \leq 3

cos (6 x)

f (x) = 2 + x^{3}

\frac{5 x}{( 2 x ^{2} + 8 )}

f (x) = 2 x^{2} - 5 x + 1

\frac{3 x}{x - 1}

What is the range of y(θ)=3cos(θ+pi) ?
The range of y(θ)=3cos(θ+pi) is -3<= f(θ)<= 3