en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of g(x)=5x^2+2

Solution

range

g (x) = 5 x^{2} + 2

Solution

f (x) \geq 2

+1

Interval Notation

[2, \infty)

Solution steps

Vertex of

5 x^{2} + 2 :

Minimum

(0, 2)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 5,

Vertex

(x_{v}, y_{v}) = (0, 2)

f (x) \geq 2

Popular Examples

inverse of f(x)=(4t)/(3t-8)inverse

f (x) = \frac{4 t}{3 t - 8}

domain of f(x)=sqrt(7x)domain

f (x) = 7 x

inverse of y=(8)^x inverse

y = (8)^{x}

inverse of f(x)= 2/x+3 inverse

f (x) = \frac{2}{x} + 3

range of f(x)=5x+sqrt(x^2+6)range

f (x) = 5 x + x^{2} + 6

Frequently Asked Questions (FAQ)

What is the range of g(x)=5x^2+2 ?
The range of g(x)=5x^2+2 is f(x)>= 2