What is the domain of f(x)= 1/((x+2)^2) ?

The domain of f(x)= 1/((x+2)^2) is x -2

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domain of f(x)= 1/((x+2)^2)

domain

f (x) = \frac{1}{( x + 2 ) ^{2}}

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

f (x) = 2 x^{7} - 3

\frac{x ^{2} + 4 x + 3}{- x ^{2} - x + 6}

\frac{x}{x + 8}

f (x) = ln (e^{x} - 3)

y = \frac{1}{2} x + 2

What is the domain of f(x)= 1/((x+2)^2) ?
The domain of f(x)= 1/((x+2)^2) is x<-2\lor x>-2