What is the domain of f(x)=sqrt(x^3+1) ?

The domain of f(x)=sqrt(x^3+1) is x>=-1

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domain of f(x)=sqrt(x^3+1)

domain

f (x) = x^{3} + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

x^{2} - 6

f (x) = x - 3 + \frac{2}{x}

(- 2, - 2), (4, 4)

(6 - 4) m = \frac{2}{3}

f (x) = \frac{( ∣ x - 5 ∣ )}{( x - 3 )}

What is the domain of f(x)=sqrt(x^3+1) ?
The domain of f(x)=sqrt(x^3+1) is x>=-1