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Popular >

midpoint (-2,4),(4,-2)

Solution

midpoint

(- 2, 4), (4, - 2)

Solution

(1, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 2, 4), (x_{2}, y_{2}) = (4, - 2)

= (\frac{4 - 2}{2}, \frac{- 2 + 4}{2})

Refine

= (1, 1)

Popular Examples

domain of f(x)=x^2+8 domain

f (x) = x^{2} + 8

inverse of x^2+8x+12 inverse

x^{2} + 8 x + 12

asymptotes of f(x)=arctan(x)+arctan(1/x)asymptotes

f (x) = arctan (x) + arctan (\frac{1}{x})

extreme f(x)=-x^2+8x-7 extreme points

f (x) = - x^{2} + 8 x - 7

range of (x^3-2x^2-3x)/(x-3)range

\frac{x ^{3} - 2 x ^{2} - 3 x}{x - 3}

Frequently Asked Questions (FAQ)

What is the midpoint (-2,4),(4,-2) ?
The midpoint (-2,4),(4,-2) is (1,1)