What is the critical f(x)=4x^4-16x^2+17 ?

The critical f(x)=4x^4-16x^2+17 is x=-sqrt(2),x=0,x=sqrt(2)

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critical f(x)=4x^4-16x^2+17

critical points

f (x) = 4 x^{4} - 16 x^{2} + 17

x = - 2, x = 0, x = 2

Solution steps

4 x^{4} - 16 x^{2} + 17

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

4 x^{4} - 16 x^{2} + 17 : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

tan (e^{5 t}) + e^{t a n (5 t)}

- 5 \cdot 2^{x}

ln (t + 1)

f (x) = 10 x - 3

What is the critical f(x)=4x^4-16x^2+17 ?
The critical f(x)=4x^4-16x^2+17 is x=-sqrt(2),x=0,x=sqrt(2)