What is the domain of ((x-1)(x+3))/(x^2-4) ?

The domain of ((x-1)(x+3))/(x^2-4) is x 2

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domain of ((x-1)(x+3))/(x^2-4)

domain

\frac{( x - 1 ) ( x + 3 )}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

4 x - 6 y = - 8

f (x) = 2 x^{5} - 3 x + 7

f (x) = csc (x)

f (x) = \frac{9 e ^{x}}{e ^{x} - 5}

f (x) = x^{\frac{1}{7}} (x + 8)

What is the domain of ((x-1)(x+3))/(x^2-4) ?
The domain of ((x-1)(x+3))/(x^2-4) is x<-2\lor-2<x<2\lor x>2