What is the inverse of f(x)=4x^2+7 ?

The inverse of f(x)=4x^2+7 is (sqrt(x-7))/2 ,-(sqrt(x-7))/2

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inverse of f(x)=4x^2+7

inverse

f (x) = 4 x^{2} + 7

\frac{x - 7}{2}, - \frac{x - 7}{2}

Solution steps

y = 4 x^{2} + 7

Replace

x

with

y

x = 4 y^{2} + 7

Solve for

y, x = 4 y^{2} + 7

\frac{x - 7}{2}, - \frac{x - 7}{2}

\frac{3 - x}{x - 2}

y = \frac{1}{2} x + 2

\frac{2 x}{x - 5}

y = \frac{1}{5} x

(- 1.1) (11.12)

What is the inverse of f(x)=4x^2+7 ?
The inverse of f(x)=4x^2+7 is (sqrt(x-7))/2 ,-(sqrt(x-7))/2