What is the domain of y=sqrt((2x+1)/(x-1)) ?

The domain of y=sqrt((2x+1)/(x-1)) is x 1

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domain of y=sqrt((2x+1)/(x-1))

domain

y = \frac{2 x + 1}{x - 1}

x \leq - \frac{1}{2} or x > 1

Interval Notation

(- \infty, - \frac{1}{2}] \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{1}{2} or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - \frac{1}{2} or x > 1

x^{2} - 25

f (x) = \frac{x ^{2} + 2}{x - 6}

\frac{2}{( x + 2 )}

6 x + 9

y = x^{2} - 6 x + 3

What is the domain of y=sqrt((2x+1)/(x-1)) ?
The domain of y=sqrt((2x+1)/(x-1)) is x<=-1/2 \lor x>1