What is the domain of f(x)= 1/((\frac{x+3){x-1})^2} ?

The domain of f(x)= 1/((\frac{x+3){x-1})^2} is x 1

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domain of f(x)= 1/((\frac{x+3){x-1})^2}

domain

f (x) = \frac{1}{( \frac{x + 3}{x - 1} ) ^{2}}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = 1

The function domain

x < - 3 or - 3 < x < 1 or x > 1

f (x) = x^{2} + 3 x + 3

y = x^{2} - 5

\frac{2 x - 1}{2 x + 1}

e^{x} - 2

f (x) = 8 (\frac{x}{2} - 3)

What is the domain of f(x)= 1/((\frac{x+3){x-1})^2} ?
The domain of f(x)= 1/((\frac{x+3){x-1})^2} is x<-3\lor-3<x<1\lor x>1