What is the range of (x+1)/(x-1) ?

The range of (x+1)/(x-1) is f(x) 1

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range of (x+1)/(x-1)

range

\frac{x + 1}{x - 1}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 1}{x - 1}

Inverse of

\frac{x + 1}{x - 1} : \frac{1 + x}{x - 1}

\frac{1 + x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{1 + x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

(4, 7), (1, 1)

lo g_{5} (x - 6) + 2

(x - 1)^{2} (x - 2)^{3}

f (x) = sin (- \frac{2 x}{3})

f (x) = \frac{3 e ^{x}}{e ^{x} - 2}

What is the range of (x+1)/(x-1) ?
The range of (x+1)/(x-1) is f(x)<1\lor f(x)>1